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Posts: 154

That's the way I see it too.

Posted by Count Strongbad (aka Rambler14) Apr 27 '12, 06:12

Given 4 teams winning in 1 conference,
you need the opposite seed winning in the other conference.

(1/2) ^ 4

Responses:

but that doesn't take into account the odds of an 8 seed beating a 1 etc though does it? -- nm - Beaker Apr 27, 06:19 12
- [deleted] 10
  - Difficult to pinpoint, it varies from year to year. -- nm - Count Strongbad Apr 27, 06:27 9
    - [deleted] 3
      - One year, the 8 seed might be really good, in a tough conference or a weak one in a weak one - Will Hunting Apr 27, 07:02 2
        
        [deleted] 1
        
        You said "odds" - Count Strongbad Apr 27, 07:56
    - 1 way to come up with it is look at the number of 8 seeds that won over the past 10 years, 7 seeds, 6 seeds, etc. -- nm - Count Strongbad Apr 27, 06:28 4
      - 1 seeds are 26-10 since the format changed in1994 -- nm - mafic Apr 27, 06:44 2
        
        2 are 19-16, 3 are 22-13, 4 also 22-13. -- nm - mafic Apr 27, 06:53 1
        
        (+1 to the wins for all those higher seeds. apparently I'm bad at math today.) -- nm - mafic Apr 27, 07:01
      - we'll just go with your first answer and assume that the odds of 8 over 1 are offset by 1 over 8 etc :) -- nm - Beaker Apr 27, 06:32
- Doesn't that kind of thing happen in the NHL a lot more often than NBA? - Count Strongbad Apr 27, 06:22

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