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In response to
"Where's nubby? What would the gravity be on a planet 2.6 times Earth's size and 7 times Earth's weight? -- nm"
by
TWuG
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ok, an attempt at the formula
Posted by
Beryllium (aka grayman)
Sep 5 '13, 09:38
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g = G * M / r^2
G = (6.67 * 10^-11)
M = ((5.98 * 10^24) *7)
r^2 = ((6.378 * 10^6)*2.6)^2
= 10.1533m.s^2
Earth's answer is 9.81m/s^2. This planet is 10.15m/s^2. So it's like 1.035 Gs ...
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