ST Alpha - "You can't argue that .9999... = 1 *because* .9999.... = 1. That's circular logic." (Reading a Post)

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In response to "Yes you do, because .999.... = 1 :) -- nm" by oblique

You can't argue that .9999... = 1 because .9999.... = 1. That's circular logic.

Posted by TWuG Mar 5 '10, 13:03

Infinite 9s isn't different enough from 1 to matter. But it *is* different.

It's the error of converting between fractions and decimals that makes it appear the it isn't different in any way.

Responses:

we're not arguing "it is because it is". There's a couple proofs been offered. - Reagen Mar 5, 13:05 7
- Yes. There. Is. It's just "infinitesimally small." -- nm - JaxSean Mar 5, 13:07 2
  - but because infinity never stops, there is no difference. -- nm - Reagen Mar 5, 13:08 1
    - there will always be a difference itss just getting idefinately smaller and smaller -- nm - Danedukenuuk Mar 5, 13:11
- part of the problem I have is that you say "when you go out to infinity" like its a place you can stop at -- nm - crash davis Mar 5, 13:06 3
  - Yeah. Infinity can never be reached. That .9 keeps trying to be 1, but it'll never arrive. It's like Zeno's Paradox. - TWuG Mar 5, 13:10
  - No, it's an acknowledgement that it *can't* stop. -- nm - mara Mar 5, 13:08 1
    - and thus it can never be equal, because the difference can't be stopped at either -- nm - crash davis Mar 5, 13:09

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You can't argue that .9999... = 1 *because* .9999.... = 1. That's circular logic.

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You can't argue that .9999... = 1 because .9999.... = 1. That's circular logic.